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1/2^(x+5)=16^x
We move all terms to the left:
1/2^(x+5)-(16^x)=0
Domain of the equation: 2^(x+5)!=0We multiply all the terms by the denominator
x∈R
-16^x*2^(x+5)+1=0
Wy multiply elements
-32x^2(x+1=0
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